100X^2+4x-960=0

Solution for 100X^2+4x-960=0 equation:

100X^2+4X-960=0

a = 100; b = 4; c = -960;
Δ = b2-4ac
Δ = 42-4·100·(-960)
Δ = 384016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384016}=\sqrt{16*24001}=\sqrt{16}*\sqrt{24001}=4\sqrt{24001}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{24001}}{2*100}=\frac{-4-4\sqrt{24001}}{200}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{24001}}{2*100}=\frac{-4+4\sqrt{24001}}{200}
$